B^3/2+2b=1

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Solution for B^3/2+2b=1 equation: 



^3/2+2B=1

We move all terms to the left:

^3/2+2B-(1)=0

determiningTheFunctionDomain
2B-1+^3/2=0

We multiply all the terms by the denominator


2B*2-1*2+^3=0

We add all the numbers together, and all the variables

2B*2=0

Wy multiply elements

4B=0

B=0/4

B=0

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